**Digital Measurement of Main Frequency:**

The conventional method of measuring the frequency of an electrical signal consists of counting the number of cycles of the input electrical signal during a specified gate interval. The length of the gate interval decides the resolution of the Digital Measurement. The shorter the gate interval, the lesser is the resolution. Now, for frequencies of the order of kHz and above, it is possible to get a resolution of 0.1% of better with a nominal gate time of 1 (sec). But for low frequencies, in order to obtain a resolution of even 0.5%, the gate time has to be considerably larger. For example, consider the case when the input electrical signal frequency is around 50 Hz. In order to obtain a resolution of 0.1 Hz, the gate interval has to be 10 seconds and in order to obtain a resolution of 0.01 Hz, the gate interval has to be 100 s. These gate periods of 10 s and 100 s are too long and in many cases it is desirable to obtain an indication of the frequency in far less time. Hence, direct or ordinary frequency counters are at a great disadvantage when it comes to low frequency measurements.

For the mains frequency monitor, the frequency range of interest is rather narrow, (50 ± 5%) Hz. The technique employed in the Digital Measurement of mains frequency, yields only a parabolic calibration curve. But within the narrow frequency range, which in this case is (50 ± 5%) Hz, the calibration is conveniently flat. Hence, the error due to the non-linear calibration is less than 0.2% at a frequency deviation as large as 5% from the centre frequency, which is 50 Hz. The error is 0.02% at a frequency deviation as large as 2% from the centre frequency and as the frequency approaches the centre value of 50 Hz, the error approaches zero.

**The principle that backs up this technique is as follows.**

Consider the relationship between the frequency and time period of the input electrical signal, f = 1/T. For an ac power line, the desired frequency is 50 Hz; let us denote it as F_{50}. If we denote the corresponding period by T_{50}, then T_{50} = 1/50 s = 20 ms. Now, let us further denote any frequency x as F, and the corresponding period as _{T.} Now, we introduce a new time scale for measuring the period of the electrical input signal whose frequency Digital Measurement is desired. Let us formulate the relationship between the MKS scale and the new scale as 20 ms = 50 ku (ku = kilounit), where ku is the unit of the new time scale. Therefore, 1 s = 50 1/20 x 1000 = 2500 ku.

Let us determine the periods corresponding to various frequencies from 45 Hz to Hz in terms of ku.

**T45 = 1/45 s = 2500/45 ku = 55.55 ku**

**T46 = 1/46 s = 2500/46 ku = 54.35 ku**

**T47 = 1/47 s = 2500/47 ku = 53.19 ku**

**T48 = 1/48 s = 2500/48 ku = 52.08 ku**

**T49 = 1/49 s = 2500/49 ku = 51.02 ku**

**T _{50} = 1/50 s = 2500/50 ku = 50.00 ku**

**T51 = 1/51 s = 2500/51 ku = 49.02 ku**

**T52 = 1/52 s = 2500/52 ku = 48.08 ku**

**T53 = 1/53 s = 2500/53 ku = 47.16 ku**

**T54 = 1/54 s = 2500/54 ku = 46.29 ku**

**T55 = 1/55 s = 2500/55 ku = 44.44 ku**

Now within this narrow frequency range of 45 — 55 Hz, we can form an empirical relation between the frequency and period of signals, as F_{x}. = 100 —T_{x}, where F_{x} is the frequency in Hz and T is the period in ku.

In order to determine the frequency of the input electrical signal, the period of the input signal has to be measured in terms of ku and then subtracted from 100. If an indication of the frequency F_{x} correct to 1 Hz (resolution is 1 Hz), is sufficient, then it is enough if the period T_{x} of the input signal is measured correct to 1 ku. In order to obtain 4 digit indication, the period T_{x} of the input signal has to be measured correct to 0.01 ku. To determine the period of the input electrical (power line) signal in terms of 0.01 ku, we need a reference signal whose period is 0.01 ku. This signal is obtained from a stable crystal controlled reference oscillator. The number of cycles of this reference signal during 1 cycle of the input signal gives the period T_{x} in terms of 0.07 ku. Rather than employing separate circuitry to determine the period and then subtracting it from 100, an UP/DOWN counter is used in the down counted mode. Thus the processes of counting the period and doing the subtraction are done simultaneously by the same circuitry.

The schematic diagram shown in Fig. 6.18, is the circuitry of the digital mains frequency Digital Measurement, consisting of the input wave shaper, reference clock generator, sequence control logic unit, counter display and intermediate latch circuitry.

Let us analyze the circuit, assuming the input signal is exactly 50 Hz. When the reference clock frequency is 1 MHz, there will be 20,000 pulses in the 20 ms period. These 20,000 pulses are divided by the other two flip-flops by a factor of 4, to get 5000 pulses in the measuring period of 20 ms. Now these pulses are counted down in the 10000 modulo counter and are displayed.

Let us consider the case, when the input signal frequency is 48 Hz. The period i.e. 1/48 s = 20.83 ms. Within this period, the number of pulses will be 5208. (For 20 ms the count is 5000, hence for 20.83 ms the count is

Therefore, 20.83 ms the count is 5208). Now, these pulses are counted down and the display reading is 10000 — 5208 = 4792; 48 Hz is displayed as 47.92 Hz.

**Digital Tachometer:**

The technique employed in measuring the speed of a rotating shaft is similar to the technique used in a conventional frequency counter, except that the selection of the gate period is in accordance with the rpm calibration.

Let us assume, that the rpm of a rotating shaft is R. Let P be the number of pulses produced by the pick up for one revolution of the shaft. Therefore, in one minute the number of pulses from the pick up is R x P. Then, the frequency of the signal from the pick up is (R x P)/60. Now, if the gate period is G s the pulses counted are (R x P x G)/60. In order to get the direct reading in rpm, the number of pulses to be counted by the counter is R. So we select the gate period as 60/P, and the counter counts

and we can read the rpm of the rotating shaft directly. So, the relation between the gate period and the number of pulses produced by the pickup is G = 60/P. If we fix the gate period as one second (G = 1 s), then the revolution pickup must be capable of producing 60 pulses per revolution.

Figure 6.19 shows a schematic diagram of a digital tachometer.

**Digital pH Meter:**

The Digital Measurement of hydrogen ion activity (pH) in a solution can be accomplished with the help of a pH meter. For those unfamiliar with the terminology, a very brief review is included.

pH is a quantative measure of acidity. If the pH is less than 7, the solution is acidic (the lower the pH, the greater the acidity). A neutral solution has a pH of 7 and alkaline (basic) solutions have a pH greater than 7.

The pH unit is defined as

**pH = — log (concentration of H ^{+})**

**where **

**H**^{+}is the hydrogen or hydronium ion.

A digital pH meter differs from an ordinary pH meter, in this the meter is replaced by an analog to digital converter (ADC) and a digital display. A frequently used ADC for this application is the dual slope converter. A basic block diagram of a digital pH meter is shown in Fig. 6.20.

The dual slope circuit produces a pulse which has a duration proportional to the input signal voltage, that is, a T pulse width signal. The pulse width is converted to a digital signal using the pulse to turn an oscillator On or Off, generating a count digital signal. The count signal is in turn counted or converted to a parallel digital signal for display by the counter.