Answer

Step by step solution by experts to help you in doubt clearance & scoring excellent marks in exams.

Updated On: 10-9-2020

Apne doubts clear karein ab Whatsapp par bhi. Try it now.

CLICK HERE

Loading DoubtNut Solution for you

Watch 1000+ concepts & tricky questions explained!

204.3 K+

10.2 K+

Text Solution

`(1)/(0.693)``2 xx 0.693``0.693``2//0.693`

Answer :

BSolution :

`t_(1//2)` for 1st order reaction `= (0.693)/(k)` <br> `t_(1//2)` for zero reaction `= ([A_(0)])/(2k')` <br> Initial rate for 1st order reaction `(r_(1))=k[A_(0)]` <br> Initial rate for zero reaction `(r_(0))=k'` <br> `:. (r_(1))/(r_(0))=(k[A_(0)])/(k')` <br> But (0.693)/(k)=([A_(0)])/(2k')` <br> `:. (k[A_(0)])/(k')=([A_(0)])/(2k')` <br> `:. (k[A_(0)])/(k')=2xx0.693` <br> i.e., `(r_(1))/(r_(0))=2xx0.693`.**Introduction And Rate Of A Reaction**

**Units Of Rate Of Reaction And Expression Of Rate**

**Factors Influencing The Rate Of Reaction**

**Law Of Mass Action And Rate Law**

**Order And Molecularity**

**Derivation And Characteristics**

**Examples And Numericals Of Zero Order Reaction**

**Derivation**

**Characteristics Of A First Order Reaction**

**Examples And Numericals Of First Order Reaction**